In the diagram above, PQT is an isosceles triangle.|PQ| =...
In the diagram above, PQT is an isosceles triangle.|PQ| = |QT|, ∠SRQ = 75°, ∠QPT = 25° and PQR is straight line. Find ∠RST
20o
50o
55o
70o
75o
Correct answer is C
< PTQ = 25° (base angles of an isos. triangle)
∴ < PQT = 180° - (25° + 25°) = 130° (sum of angles in triangle PQT)
\therefore < RST = 130° - 75° = 55° (exterior angle = sum of 2 opp. interior angles)
Similar Questions
Differentiate \frac{6x^3 - 5x^2 + 1}{3x^2} with respect to x...
The table gives the distribution of outcomes obtained when a die was rolled 100 times. What is th...
The angle of a sector of a circle of diameter 8cm is 135°. Find the area of the sector [Take \(\...
In the diagram O is the center of the circle, if ∠QRS = 62o, find the value of ∠SQR. ...
Find the sum of the interior angle of a pentagon. ...
If the mean of 3, 5, 8, k, 14 and 17 is 11, what is the value of k ...
What is the n-th term of the sequence 2, 6, 12, 20...? ...
Simplify 2.04 × 3.7 (Leave your answer in 2 decimal place) ...