13
5
13/5
12/5
5/12
Correct answer is D
cosθ=513
⟹ In the right- angled triangle, with an angle θ, the adjacent side to θ = 5 and the hypotenuse = 13.
∴
opp^2 = 169 - 25 = 144 \implies opp = \sqrt{144}
= 12.
\tan \theta = \frac{opp}{adj} = \frac{12}{5}