In the diagram above, |PQ| = |QR|, |PS| = |RS|, ∠PSR = 30<...
In the diagram above, |PQ| = |QR|, |PS| = |RS|, ∠PSR = 30o and ∠PQR = 80o. Find ∠SPQ.
A.
15o
B.
25o
C.
40o
D.
50o
E.
55o
Correct answer is B
Join PR
QRP = QPR
= 180 - 80 = 100/20 = 50o
SRP = SPR
= 180 - 30 = 150/2 = 75o
∴ SPQ = SPR - QPR
= 75 - 50 = 25o
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