1.2 x 10−5K−1
2.5x 10−5K−1
3.5x 10−5K−1
4.5x 10−5K−1
5x 10−5K−1
Correct answer is E
α=I2−I1I1(θ2−θ1)⇒40.05−4040×(45−20)=5.0×10−5
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