What is the equation of the line PQ?
y = x - 5
y = x + 3
y = x + 5
y = 2x + 3
y = 2x - 3
Correct answer is C
The points P(-2, 3) and Q(2, 7) are on the line.
Gradient of the line = \(\frac{7 - 3}{2 - (-2)}\)
= \(\frac{4}{4}\)
= 1
y = x + b
To find the intercept, we have
7 = 2 + b or 3 = -2 + b.
Solving for b, we get b = 5.
\(\therefore\) The line is y = x + 5.
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