JAMB Past Questions and Answers - Page 1249

6,241.

The electronic configuration of an element is 1S\(^2\) 2S\(^2\) 2P\(^6\) 3S\(^2\) 3P\(^3\). How many unpaired electrons are there in the element?

A.

5

B.

4

C.

3

D.

2

Correct answer is C

Once you figure out the electron configuration, you fill up the corresponding orbitals with electrons, any left with one is considered unpaired. Since 1s can only hold 2 electrons, and P has 15, that's obviously filled and has no unpaired electrons. The same is for 2s which holds 2, 2p which holds 6, 3s which holds 2.

However 3p can hold 6 electrons and in order for that to be filled up you would need to have an element of 18 electrons. So you fill up as much as you can in 3p by first adding 1 electron to each energy level. 3p has 3 energy levels and there are only 3 electrons left to distribute, so each of those energy levels only gets 1, because you have to fill them all with one before you can start adding a second.

So since you are only able to fill one electron in each of the three energy levels of the 3p orbital, that leaves the orbital open for 1 more electron in each of its energy levels. So there are 3 unpaired electrons in P.

6,242.

Jan. 1 Received 1,000 units at N10 each
Jan. 2 Received 2,000 units at N12 each
Jan. 3 Issued 1,500 units
Jan. 4 Received 1,000 units at N11 each
Jan. 5 Issued 1,000 units

What is the value of closing stock using simple average?

A.

N11,500

B.

N17,000

C.

N16,500

D.

N28,500

Correct answer is C

In this method of stock valuation, the average unit cost is calculated by multiplying the total of the unit costs by the number of receiving. 

issue price method Date Receipt Issue Balance
Simple average   Qty price Value Dispatch Qty Balance
1/1 1000 10 10000 - 1000
2/1 2000 12 24000 - 3000
3/1 - - - 1500 1500
4/1 1000 11 11000 - 2500
  5/1 - - - 1000 1500
Total   4000 33   2500 1500

The closing stock using simple average =

(33 ÷ 3) x 1500 = 16500

 

6,243.

Which of the following factors will speed up the rate of evolution of carbon (iv) oxide in the reaction below?
2HCl + CaCO\(_3\) → CaCl\(_2\) + H\(_2\)O + CO\(_2\)

A.

Increasing the concentration of the acid

B.

Increasing the surface area of CaCO\(_3\)

C.

A and B

D.

Reducing the concentration of the acid

Correct answer is C

The following factors increase a reaction rate
- Increase in concentration of reactants
- Increase in temperature
- Addition of catalyst
- Increase in the surface area of reactant(s)

6,244.

Jan. 1 Received 1,000 units at N10 each
Jan. 2 Received 2,000 units at N12 each
Jan. 3 Issued 1,500 units
Jan. 4 Received 1,000 units at N11 each
Jan. 5 Issued 1,000 units

Using FIFO method, what is the value of the closing stock?

A.

N34,000

B.

N29,000

C.

N17,000

D.

N12,000

Correct answer is C

FIFO means first in first out. This method assumes that the oldest products in a company’s inventory have been sold first. The costs paid for those oldest products are the ones used in the calculation.

issue price method Date Receipt     Issue   Balance    
FIFO   Qty price Value Qty price Value Qty value
1/1 1000 10 10000 - - - 1000 10000
2/1 2000 12 24000 - - - 3000 34000
3/1 - - - 1500 - 1500 1500 18000
4/1 1000 11 11000 - - 2500 2500 27,500
  5/1 - - - 1000   1500 1500 16500

From the table above, value of closing stock using FIFO = 

Total closing stock = 1500

previous stock bought at N12 = 500 units

Last stock bought at N11 = 1000 units

12 x 500 + (11 x 1000) = 17,000

 

6,245.

The part of the total energy of a system that accounts for the useful work done in a system is known as

A.

Enthalpy change

B.

None of the above

C.

Gibb's free energy

D.

Entropy

Correct answer is C

Gibb's free energy is the fraction of the total energy of a system that accounts for how much useful work can be done in a system.