JAMB Past Questions and Answers - Page 1375

6,871.

Ethanol is soluble in water due to the presence of a

A.

Carbonyl group

B.

Hydroxyl group

C.

Phenyl group

D.

Methyl group

Correct answer is B

No explanation has been provided for this answer.

6,872.

If the total discount allowed in a cash book was N230 and the total discount received was N255, which of the following is true concerning the two discounts?

A.

They must be balanced in the cash book and the difference taken to the debtors ledger

B.

They must be balanced in the cash book and the difference taken to the trial balance

C.

They should not be balanced in the cash book before being taking to the trial balance

D.

They should not appear in the trial balance as they were already either received or paid out

Correct answer is D

No explanation has been provided for this answer.

6,873.

Diamond cannot be used

A.

In making bicycle chains

B.

As abrasives

C.

In cutting glass and metals

D.

As dies for drawing wires

Correct answer is A

No explanation has been provided for this answer.

6,875.

What volume of 0.5M H2SO4 will exactly neutralize 20cm3 of 0.1M NaOH Solution?

A.

2.0cm 3

B.

5.0cm 3

C.

6.8cm 3

D.

8.3cm 3

Correct answer is A

The balanced equation is given as:

\(H_{2}SO_{4} + 2NaOH \to Na_{2}SO_{4} + 2H_{2}O\)

Molarity of \(NaOH = 0.1M\)

Volume of \(NaOH = 20cm^{3}\)

Molarity of \(H_{2}SO_{4} = 0.5M\)

mol NaOH = \(0.1 \times 20cm^{3} = 2molNaOH\)

⇒ \(2mol NaOH \times \frac{1mol H_{2}SO_{4}}{2mol NaOH} = 1 mol H_{2}SO_{4}\)

\(volume of H_{2}SO_{4} = \frac{mole of H_{2}SO_{4}}{molarity of H_{2}SO_{4}}\)

= \(\frac{1 mole}{0.5 M} = 2cm^{3} H_{2}SO_{4}\)