\(\frac{2P}{\pi}\)
\(\frac{P}{\sqrt{\pi}}\)
\(\frac{P}{\sqrt{2\pi}}\)
2\(\frac{P}{\pi}\)
Correct answer is D
Surface area of a sphere = 4\(\pi\)r2
\(\frac{1}{16}\) of 4\(\pi\)r2
= \(\frac{\pi r^2}{4}\)
P = \(\frac{\pi r^2}{4}\)
r = 2\(\frac{P}{\pi}\)
25cm
18cm
15cm
24cm
27cm
Correct answer is C
Area = L x B
L - B = 6
L = 6 + B
area = 135
B(6 + B) = B2 + 6B - 135 = 0
B = 9
L = 6 + 9
= 15
1.0622
10.6225
0.1328
0.3218
2.0132
Correct answer is C
\(4t^{2} + 7t - 1 = 0\)
Using a = 4, b = 7, c = -1.
\(x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}\)
= \(\frac{-7 \pm \sqrt{7^{2} - 4(4)(-1)}}{2(4)}\)
= \(\frac{-7 \pm \sqrt{49 + 16}}{8}\)
= \(\frac{-7 \pm \sqrt{65}}{8}\)
= \(\frac{-7 \pm 8.0623}{8}\)
The positive answer = \(\frac{-7 + 8.0623}{8} = \frac{1.0623}{8}\)
\(\approxeq 0.1328\) (4 decimal place)
Evaluate \(\frac{6.3 \times 10^5}{8.1 \times 10^3}\) to 3 significant fiqures
77.80
778.0
7.870
8.770
88.70
Correct answer is A
\(\frac{6.3 \times 10^5}{8.1 \times 10^3}\)
\(\frac{7}{9} \times 10^{2}\)
= \(0.77778 \times 10^{2}\)
= \(77.778 \approxeq 77.80\)
10011
111011
111000
11001
110011
Correct answer is D
\(\begin{array}{c|c} 2 & 25\\2 & 12 R 1\\2 & 6 R 0\\2 & 3 R 0\\2 & 1 R 1\end{array}\)
= (11001)