1.40 χ 102 dm3
14.0 χ 102 cm3
1.40 χ 10-2 dm-2
14.0 χ 10-2 cm3
Correct answer is A
Na2C2O4 + CaCl2 → CaC2O4 + 2NaCl
molar mass of Na2C2O4 = 134
molarity in 1000g H2O = (1.9)/(134) = 0.014 m
but in 502 g mole = (0.014)/(50) χ 1000 = 0.28 m
M1V1 = M2V2
V2 = (M1V1)/(M2) = (0.28 χ 50)/(0.1) = 140
= 1.40 χ 102 dm3
solid particles dispersed in liquid
solid or liquid particles dispersed in gas
gas or liquid particles dispersed inliquid
liquid particles dispersed inliquid
Correct answer is B
No explanation has been provided for this answer.
0.13
0.25
1.25
2.00
Correct answer is C
Solubility in moles per dm3
No of moles = (20)/(159.5) χ 0.125 moles
in 100 g of moles = (0.125)/(100) χ 1000 = 1.25 moles
is deliquescent
is hydroscopic
has some molecules of water of crystallization
is efflorescent
Correct answer is A
No explanation has been provided for this answer.
50.2
47.0
4.70
0.47
Correct answer is C
Pb(NO3)2 + H2S → PbS + 2HNO3
34 g H2S → 239 g pbs
5.02g pbs → (34)/(237g) χ 5.02 g = 0.714 g
34g → 22.4 dm3
=0.714 → (22.4)/34g) χ 100 = 4.70