JAMB Mathematics Past Questions & Answers - Page 310

1,546.

Find r, if 6r7\(_8\) = 511\(_9\)

A.

3

B.

2

C.

6

D.

5

Correct answer is A

6r7\(_8\) = 511\(_9\)

6 x 8\(^2\) + r x 8\(^1\) + 7 x 8\(^0\) = 5 x 9\(^2\) + 1 x 9\(^1\) + 1 x 9\(^0\)

6 x 64 + 8r + 7 x 1 = 5 x 81 + 9 + 1 x 1

384 + 8r + 7 = 405 + 9 + 1

 

8r = 415 - 391

 8r = 24

r = \(\frac{24}{8}\)

= 3

1,547.

Find the derivative of \(\frac {\sin\theta}{\cos\theta}\)

A.

sec2 \(\theta\)

B.

tan \(\theta\) cosec \(\theta\)

C.

cosec \(\theta\)sec \(\theta\)

D.

cosec2\(\theta\)

Correct answer is A

\(\frac {\sin\theta}{\cos\theta}\)

\(\frac{\cos \theta {\frac{d(\sin \theta)}{d \theta}} - \sin \theta {\frac{d(\cos \theta)}{d \theta}}}{\cos^2 \theta}\)

\(\frac{\cos \theta. \cos \theta - \sin \theta (-\sin \theta)}{cos^2\theta}\)

\(\frac{cos^2\theta + \sin^2 \theta}{cos^2\theta}\)

Recall that sin2 \(\theta\) + cos2 \(\theta\) = 1

\(\frac{1}{\cos^2\theta}\) = sec2 \(\theta\)

1,548.

Find the probability that a number picked at random from the set(43, 44, 45, ..., 60) is a prime number.

A.

\(\frac{2}{3}\)

B.

\(\frac{1}{3}\)

C.

\(\frac{2}{9}\)

D.

\(\frac{7}{9}\)

Correct answer is C

Prime numbers = (43,47,53,59)

N = (43, 44, 45,..., 60)

The universal set contains 18 numbers.

The prime numbers between 43 and 60 are 4

Probability of picking a prime number = \(\frac{4}{18}\)

= \(\frac{2}{9}\)

1,549.

In how many ways can five people sit round a circular table?

A.

24

B.

60

C.

12

D.

120

Correct answer is A

The first person will sit down and the remaining will join. i.e. (n - 1)! = (5 - 1)! = 4! = 24 ways

1,550.

In how many was can the letters of the word ELATION be arranged?

A.

6!

B.

7!

C.

5!

D.

8!

Correct answer is B

ELATION Since there are 7 letters. The first letter can be arranged in 7 ways, , the second letter in 6 ways, the third letter in 5 ways, the 4th letter in four ways, the 3rd letter in three ways, the 2nd letter in 2 ways and the last in one way. therefore, 7 x 6 x 5 x 4 x 3 x 2 x 1 = 7! ways