If 2x\(^2\) - kx - 12 is divisible by x-4, Find the value of k.
4
5
6
7
Correct answer is B
2x2 - kx - 12 is divisible by x-4
implies x is a factor ∴ x = 4
f(4) implies 2(4)2 - k(4) - 12 = 0
32 - 4k - 12 = 0
-4k + 20 = 0
-4k = -20
k = 5
Make Q the subject of formula when \(L=\frac{4}{3}M\sqrt{PQ}\)
\(\frac{9L^2}{16M^2P}\)
\(\frac{3L}{4M\sqrt{P}}\)
\(\frac{\sqrt{3L}}{4MP}\)
\(\frac{3L^2}{16M^2}P\)
Correct answer is A
\(L=\frac{4}{3}M\sqrt{PQ}\\
=\frac{3}{4M} \times L = \sqrt{PQ}\\
=\left(\frac{3L}{4M}\right)^2=(\sqrt{PQ})^2\\
=\frac{9L^2}{16M^2}=PQ\\
=Q=\frac{9L^2}{16M^2 P}\)
30
40
50
60
Correct answer is B
No explanation has been provided for this answer.
If X = {n\(^2\) + 1:n = 0,2,3} and Y = {n+1:n=2,3,5}, find X∩Y.
{1,3}
{5,10}
∅
{4,6}
Correct answer is C
X = {1,5,10}
Y = {3,4,6}
X∩Y = ∅
(-3, -2)
(-2, 3)
(3,2)
(2,-3)
Correct answer is A
\(\frac{1+\sqrt{2}}{1-\sqrt{2}} \times \frac{1+\sqrt{2}}{1+\sqrt{2}}\\
=\frac{1+(1+\sqrt{2})+\sqrt{2}(1+\sqrt{2})}{1^2 - (\sqrt{2})^2}\\
=\frac{(1+\sqrt{2}+\sqrt{2}+2)}{1-2}\\
=\frac{3+2\sqrt{2}}{-1}\\
=-3-2\sqrt{2}\\
∴X and Y = -3 and -2\)