JAMB Mathematics Past Questions & Answers - Page 374

1,866.

Compute 1100112 + 111112

A.

10010102

B.

10100102

C.

10001102

D.

10001002

Correct answer is B

1100112 + 111112 = 10100102

1,867.

Evaluate \(\frac{2}{6-5\sqrt{3}}\)

A.

\(-\left(\frac{12}{39}-\frac{10\sqrt{3}}{39}\right)\)

B.

\(\frac{12}{39}-\frac{10\sqrt{3}}{39}\)

C.

\(-\left(\frac{12}{39}+\frac{10\sqrt{3}}{39}\right)\)

D.

\(\frac{12}{39}+\frac{10\sqrt{3}}{39}\)

Correct answer is A

\(\frac{2}{6-5\sqrt{3}} = \frac{2}{6-5\sqrt{3}} \times \frac{6+5\sqrt{3}}{6+5\sqrt{3}}\\
=\frac{2(6+5\sqrt{3})}{(6-5\sqrt{3})(6+5\sqrt{3})}\\
=\frac{12+10-\sqrt{3}}{36-25(3)}\\
=\frac{12+10-\sqrt{3}}{36-75}\\
=\frac{12+10-\sqrt{3}}{-39}\\
=-\left(\frac{12}{39}-\frac{10\sqrt{3}}{39}\right)\)

1,868.

Find the tax on an income of N20,000 if no tax is paid on the first N10,000 and tax is paid at N50 in N1000 on the next N5000 and at N55 in N1000 on the remainder

A.

N500

B.

N552

C.

N255

D.

N525

Correct answer is D

N20,000 - N10,000 = N10,000
1st tax on N5000 at N50 per N1000
= 5*50 = N250
2nd tax on the remaining N5000 at N55 per N1000 = 5*55 = N275
Total tax paid = N250 + N275
= N525

1,870.

If (K2)\(_6\) * 3\(_6\) = 3\(_5\)(K4)\(_5\), what is the value of k?

A.

1

B.

4

C.

3

D.

2

Correct answer is D

(K2)\(_6\) * 3\(_6\) = 3\(_5\)(K4)\(_5\)

(K*6\(^1\) + 2*6\(^0\)) 3*6\(^0\) = 3*5\(^0\)(K*5\(^1\) + 4*5\(^0\))

3(6K + 2) = 3(5K + 4)

6K + 2 = 5K + 4

6K - 5K = 4 - 2

K = 2