The locus of the points which is equidistant from the line PQ forms a
perpendicular line to PQ
circle centre P
circle centre Q
pair of parallel lines to PQ
Correct answer is A
No explanation has been provided for this answer.
32\(\pi\) cm\(^2\)
4\(\pi\) cm\(^2\)
8\(\pi\) cm\(^2\)
16\(\pi\) cm\(^2\)
Correct answer is C
Angle of major sector = 360° - 120° = 240°
Area of major sector : \(\frac{\theta}{360} \times \pi r^{2}\)
r = \(\frac{4\sqrt{3}}{2} = 2\sqrt{3} cm\)
Area : \(\frac{240}{360} \times \pi \times (2\sqrt{3})^{2}\)
= \(8\pi cm^{2}\)
\(8\sqrt{3}\) cm
4 cm
8 cm
\(8\sqrt{2}\) cm
Correct answer is D
Length of chord = \(2r \sin (\frac{\theta}{2})\)
= \(2 \times 8 \times \sin (\frac{90}{2})\)
= \(16 \times \frac{\sqrt{2}}{2}\)
= \(8\sqrt{2} cm\)
720
336
420
576
Correct answer is B
Length of the tile = 30 cm = 0.3m
Area of the tile = 0.3 \(\times\) 0,3 = 0.09 m\(^2\)
Area of the room = (7.2 \(\times\) 4.2)m\(^2\)
Number of tiles = \(\frac{7.2 \times 4.2}{0.09}\)
= 336
If the angles of a quadrilateral are (3y + 10)°, (2y + 30)°, (y + 20)° and 4y°. Find the value of y.
66°
12°
30°
42°
Correct answer is C
Sum of angles in a quadrilateral = 360°
\(\therefore\) (3y + 10) + (2y + 30) + (y + 20) + 4y = 360
10y + 60 = 360 \(\implies\) 10y = 300
y = 30°