32\(\pi\) cm\(^2\)
4\(\pi\) cm\(^2\)
8\(\pi\) cm\(^2\)
16\(\pi\) cm\(^2\)
Correct answer is C
Angle of major sector = 360° - 120° = 240°
Area of major sector : \(\frac{\theta}{360} \times \pi r^{2}\)
r = \(\frac{4\sqrt{3}}{2} = 2\sqrt{3} cm\)
Area : \(\frac{240}{360} \times \pi \times (2\sqrt{3})^{2}\)
= \(8\pi cm^{2}\)
Given that 3x - 5y - 3 = 0, 2y - 6x + 5 = 0 the value of (x, y) is...
Evaluate \(\frac{1}{3} \div [\frac{5}{7}(\frac{9}{10} -1 + \frac{3}{4})]\)...
In how many was can the letters of the word ELATION be arranged? ...
If √24 + √96 - √600 = y√6, find the value of y ...
In the diagram above, RST is a tangent to circle VSU center O ∠SVU = 50° and UV is a di...
In this figure, PQRS is a parallelogram, PS = PT and < PST = 55\(^o\). The size of <PQR is...