Given that tan x = \(\frac{2}{3}\), where 0o d" x d" 90o, Find the value of 2sinx.
\(\frac{2\sqrt{13}}{13}\)
\(\frac{3\sqrt{13}}{13}\)
\(\frac{4\sqrt{13}}{13}\)
\(\frac{6\sqrt{13}}{13}\)
Correct answer is C
tan x = \(\frac{2}{3}\)(given), is illustrated in a right-angled \(\Delta\)
thus m2 = 22 + 32
= 4 + 9 = 13
m = \(\sqrt{13}\)
Hence, 2sin x = 2 x \(\frac{2}{m}\)
2 x\(\frac{2}{\sqrt{13}}\)
= \(\frac{4}{\sqrt{13}}\)
= \(\frac{4}{\sqrt{13}} = \frac{\sqrt{13}}{\sqrt{13}}\)
= \(\frac{4\sqrt{13}}{13}\)
Find the 7th term of the sequence: 2, 5, 10, 17, 6,...
37
48
50
63
Correct answer is C
No explanation has been provided for this answer.
If \(\frac{27^x \times 3^{1 - x}}{9^{2x}} = 1\), find the value of x.
1
\(\frac{1}{2}\)
-1
Correct answer is B
\(\frac{27^x \times 3^{1 - x}}{9^{2x}} = 1\)
\(\frac{3^{3x} \times 3^{1 - x}}{3^{2(2 - x)}} = 3^0\)
\(3^{3x} \times 3^{1 - x} \div 3^{4x} = 3^0\)
\(3^{(3x + 1 - x - 4x)} = 3^0\)
\(3^{(1 - 2x)} = 3^0\)
since the bases are equal,
1 - 2x = 0
- 2x = -1
x = \(\frac{1}{2}\)
N250,000.00
N200,000.00
N150,000.00
N100,000.00
Correct answer is B
N1.00 = $0.075
N X = $15,000
X = \(\frac{1.00 \times 15000}{0.075}\)
= N200,000.00
The sum 110112, 11112 and 10m10n02. Find the value of m and n.
m = 0, n = 0
m = 1, n = 0
m = 0, n = 1
m = 1, n = 1
Correct answer is C
No explanation has been provided for this answer.
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