Given that x2 + y2 + k = 60 and x = \(\sqrt{10}\) when y = 4, find the value of k.
56
34
32
-34
-56
Correct answer is B
x\(^2\) + y\(^2\) + k = 60
(√10)\(^2\) + (4)\(^2\) + k = 60
k + 10 + 16 = 60
k = 60 - 26
k = 34
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