The following table gives the percentage distribution of population of five states, P, Q, R, S and T on the basis of poverty line and also on the basis of sex.
1:3
2:5
3:7
4:9
Correct answer is B
For State Q:
Male population below poverty line = 2.4 million.
Let the female population below poverty line be x million.
Then, 3 : 5 = 2.4 : x => x = (5 x 2.4)/3 = 4
Therefore Total population below poverty line = (2.4 + 4) = 6.4 million.
If Nq be the total population of State Q, then,
25% of Nq = 6.4 million => Nq = ( (6.4 x 100)/25 ) million = 25.6 million.
For State T:
Male population below poverty line = 6 million.
Let the female population below poverty line be y million.
Then, 5 : 3 = 6 : y => y = (3 x 6)/5 = 3.6
Therefore Total population below poverty line = (6 + 3.6) = 9.6 million.
If Nt be the total population of State T, then,
15% of Nt = 9.6 million => Nt = ( (9.6 x 100)/15 ) million = 64 million.
Thus, Required ratio = Nq/Nt = 25.6/64 = 0.4 = 2.5
The following table gives the percentage distribution of population of five states, P, Q, R, S and T on the basis of poverty line and also on the basis of sex.
2.1 million
2.3 million
2.7 million
3.3 million
Correct answer is D
Female population below poverty line for State P = 2.1 million
Let the male population below poverty line for State P be x million.
Then, 5 : 6 = x : 21 => x = (2.1 x 5)/6 = 1.75
Therefore Population below poverty line for State P = (2.1 + 1.75) million = 3.85 million.
Let the population above poverty line for State P be y million.
Since, 35% of the total population of State P is below poverty line, therefore, 65% of the total population of State P is above poverty line i.e., the ratio of population below poverty line to that above poverty line for State P is 35 : 65.
Therefore 35 : 65 = 3.85 : y => y = (65 x 3.85)/35 = 7.15
Therefore Population above poverty line for State P = 7.15 million and so, male population above poverty line for State P
= ( 6/13 x 7.15 ) million
= 3.3 million
The following table gives the percentage distribution of population of five states, P, Q, R, S and T on the basis of poverty line and also on the basis of sex.
3 million
2.43 million
1.33 million
5.7 million
Correct answer is B
Total population of State S = 7 million.
Therefore Population above poverty line
= [(100 - 19)% of 7] million
= (81% of 7) million
= 5.67 million.
And so, the number of females above poverty line in State S
= ( 3/7 x 5.67 ) million
= 2.43 million.
The following table gives the percentage distribution of population of five states, P, Q, R, S and T on the basis of poverty line and also on the basis of sex.
4.5 million
4.85 million
5.35 million
6.25 million
Correct answer is D
Let the total population of State R be x million.
Then, population of State R above poverty line
= [(100 - 24)% of x] million
= ( 76/100 x x ) million
And so, male population of State R above poverty line
= [ 2/5 x ( 76/100 x x ) ] million
But, it is given that male population of State R above poverty line= 1.9 million.
Therefore 2/5 x ( 76/100 x x ) = 1.9 => x = (5 x 100 x 1.9)/76 x 2 = 6.25
Therefore Total population of State R = 6.25 million.
The following table shows the number of new employees added to different categories of employees in a company and also the number of employees from these categories who left the company every year since the foundation of the Company in 1995.
19%
21%
27%
29%
Correct answer is D
Total number of Operators who left the Company during 1995 - 2000
= (104 + 120 + 100 + 112 + 144)
= 580.
Total number of Operators who joined the Company during 1995 - 2000
= (880 + 256 + 240 + 208 + 192 + 248)
= 2024.
Therefore Required Percentage
= ( 580/2024 x 100 ) %
= 28.66%
≈ 29%.
The following table shows the number of new employees added to different categories of employees in a company and also the number of employees from these categories who left the company every year since the foundation of the Company in 1995.
What is the pooled average of the total number of employees of all categories in the year 1997?
1325
1195
1265
1235
Correct answer is B
Total number of employees of various categories working in the Company in 1997 are:
Managers = (760 + 280 + 179) - (120 + 92) = 1007.
Technicians = (1200 + 272 + 240) - (120 + 128) = 1464.
Operators = (880 + 256 + 240) - (104 + 120) = 1152.
Accountants = (1160 + 200 + 224) - (100 + 104) = 1380.
Peons = (820 + 184 + 152) - (96 + 88) = 972.
Therefore Pooled average of all the five categories of employees working in the Company in 1997
= 1/5 x (1007 + 1464 + 1152 + 1380 + 972)
= 1/5 x (5975)
= 1195.
The following table shows the number of new employees added to different categories of employees in a company and also the number of employees from these categories who left the company every year since the foundation of the Company in 1995.
Managers
Technicians
Operators
Accountants
Correct answer is A
Number of Managers working in the Company:
In 1995 = 760.
In 2000 = (760 + 280 + 179 + 148 + 160 + 193) - (120 + 92 + 88 + 72 + 96)
= 1252.
Therefore Percentage increase in the number of Managers
= [ (1252 - 760)/760 x 100 ] % = 64.74%.
Number of Technicians working in the Company:
In 1995 = 1200.
In 2000 = (1200 + 272 + 240 + 236 + 256 + 288) - (120 + 128 + 96 + 100 + 112)
= 1936.
Therefore Percentage increase in the number of Technicians
= [ (1936 - 1200)/1200 x 100 ] % = 61.33%.
Number of Operators working in the Company:
In 1995 = 880.
In 2000 = (880 + 256 + 240 + 208 + 192 + 248) - (104 + 120 + 100 + 112 + 144)
= 1444.
Therefore Percentage increase in the number of Operators
= [ (1444 - 880)/880 x 100 ] % = 64.09%.
Number of Accountants working in the Company:
In 1995 = 1160.
In 2000 = (1160 + 200 + 224 + 248 + 272 + 260) - (100 + 104 + 96 + 88 + 92)
= 1884.
Therefore Percentage increase in the number of Accountants
= [ (1884 - 1160)/1160 x 100 ] % = 62.41%.
Number of Peons working in the Company:
In 1995 = 820.
In 2000 = (820 + 184 + 152 + 196 + 224 + 200) - (96 + 88 + 80 + 120 + 104)
= 1288.
Therefore Percentage increase in the number of Peons = [ (1288 - 820)/820 x 100 ] % = 57.07%.
Clearly, the percentage increase is maximum in case of Managers
The following table shows the number of new employees added to different categories of employees in a company and also the number of employees from these categories who left the company every year since the foundation of the Company in 1995.
What was the total number of Peons working in the Company in the year 1999?
1312
1192
1088
968
Correct answer is B
Total number of Peons working in the Company in 1999
= (820 + 184 + 152 + 196 + 224) - (96 + 88 + 80 + 120)
= 1192
The following table shows the number of new employees added to different categories of employees in a company and also the number of employees from these categories who left the company every year since the foundation of the Company in 1995.
128
112
96
88
Correct answer is D
Required difference
= (272 + 240 + 236 + 256 + 288) - (200 + 224 + 248 + 272 + 260)
= 88
A school has four sections A, B, C, D of Class IX students.
The results of half yearly and annual examinations are shown in the table given below.
Which section has the minimum failure rate in half yearly examination?
Section A
Section B
Section C
Section D
Correct answer is D
Total number of failures in half-yearly exams in a section
= [ (Number of students who failed in both exams) + (Number of students who failed in half-yearly but passed in Annual exams) ] in that section
Therefore Failure rate in half-yearly exams in Section A
= [ Number of students of Section A who failed in half-yearly/Total number of students in Section A x 100 ] %
= [ (28 + 14)/(28 + 14 + 6 + 64) x 100 ] % = [ 42/112 x 100 ] % = 37.5%
Similarly, failure rate in half-yearly exams in:
Section B [ (23 + 12)/(23 + 12 + 17 + 55) x 100 ] % = [ 35/107 x 100 ] % = 32.71%
Section C [ (17 + 8)/(17 + 8 + 9 + 46) x 100 ] % = [ 25/80 x 100 ] % = 31.25%
Section D [ (27 + 13)/(27 + 13 + 15 + 76) x 100 ] % = [ 40/131 x 100 ] % = 30.53%
Clearly, the failure rate is minimum for Section D.
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