Table Charts Questions & Answers - Page 4

Aggregate marks obtained by Tarun

    = [ (65% of 150) + (35% of 130) + (50% of 120)

          + ((77% of 100) + (80% of 60) + (80% of 40) ]

    = [ 97.5 + 45.5 + 60 + 77 + 48 + 32 ]

    = 360.

The maximum marks (of all the six subjects)

    = (150 + 130 + 120 + 100 + 60 + 40)

    = 600.

Therefore Overall percentage of Tarun = ( 360/600 x 100 ) % = 60%.

We shall find the overall percentage (for all the seven students) with respect to each subject.

The overall percentage for any subject is equal to the average of percentages obtained by all the seven students since the maximum marks for any subject is the same for all the students.

Therefore, overall percentage for:

(i) Maths = [ 1/7 x (90 + 100 + 90 + 80 + 80 + 70 + 65) ] % = [ 1/7 x (575) ] %  = 82.14%.

(ii) Chemistry = [ 1/7 x (50 + 80 + 60 + 65 + 65 + 75 + 35) ] %  = [ 1/7 x (430) ] %  = 61.43%.

(iii) Physics = [ 1/7 x (90 + 80 + 70 + 80 + 85 + 65 + 50) ] %  = [ 1/7 x (520) ] %  = 74.29%.

(iv) Geography = [ 1/7 x (60 + 40 + 70 + 80 + 95 + 85 + 77) ] %  = [ 1/7 x (507) ] %  = 72.43%.

(v) History = [ 1/7 x (70 + 80 + 90 + 60 + 50 + 40 + 80) ] %  = [ 1/7 x (470) ] %  = 67.14%.

(vi) Comp. Science = [ 1/7 x (80 + 70 + 70 + 60 + 90 + 60 + 80) ] %  = [ 1/7 x (510) ] %  = 72.86%.

Clearly, this percentage is highest for Maths.

Aggregate marks obtained by Sajal

    = [ (90% of 150) + (60% of 130) + (70% of 120)

          + (70% of 100) + (90% of 60) + (70% of 40) ]

    = [ 135 + 78 + 84 + 70 + 54 + 28 ]

    = 449

From the table it is clear that Sajal and Rohit have 60% or more marks in each of the six subjects.

Average marks obtained in Physics by all the seven students

= 1/7 x [ (90% of 120) + (80% of 120) + (70% of 120) + (80% of 120) + (85% of 120) + (65% of 120) + (50% of 120) ]

= 1/7 x [ (90 + 80 + 70 + 80 + 85 + 65 + 50)% of 120 ] 

= 1/7 x [ 520% of 120 ]

= 624/7

= 89.14

Required percentage = [ (1020 + 1240)/(8800 + 9500) x 100 ] %

= [ 2260/18300 x 100 ] %

= 12.35%.

Required percentage = [ (850 + 920 + 890 + 980 + 1350)/(7400 + 8450 + 7800 + 8700 + 9800) x 100 ] %

= [ 4990/42150 x 100 ] %

= 11.84%.

Required percentage = [ (840 + 1050 + 920 + 980 + 1020)/(7500 + 9200 + 8450 + 9200 + 8800) x 100 ] %

= [ 4810/43150 x 100 ] %

= 11.15%

The percentages of candidates qualified to candidates appeared from State P during different years are:

For 1997 ( 780/6400 x 100 ) % = 12.19%

For 1998 ( 1020/8800 x 100 ) % = 11.59%

For 1999 ( 890/7800 x 100 ) % = 11.41%

For 2000 ( 1010/8750 x 100 ) % = 11.54%

For 2001 ( 1250/9750 x 100 ) % = 12.82%

Therefore Maximum percentage is for the year 2001.

Required average = (8100 + 9500 + 8700 + 9700 + 8950)/5

= 44950/5

= 8990