\(\frac{8}{15}\)
\(\frac{13}{25}\)
\(\frac{11}{15}\)
\(\frac{13}{15}\)
Correct answer is A
Prob(RB + BR) = Total balls = 4 + 6 = 10
= prob(\(\frac{4}{10} \times \frac{6}{9}\)) + prob(\(\frac{6}{10} \times \frac{4}{9}) = \frac{24}{90} + \frac{24}{90}\)
= \(\frac{48}{90} = \frac{16}{30} = \frac{8}{15}\)
\(\sqrt{10}\)
4
5
\(\sqrt{30}\)
Correct answer is C
\(\begin{array}{c|c} x & x - x & (x - \bar{x})^2\\ \hline 15 & -6 & 36\\21 & 0 & 0\\17 & -4 & 16\\ 26 & 5 & 25 \\ 18 & -3 &9 \\ 29 & 8 & 64 \end{array}\)
\(E(x - \bar{x})^2\) = 150
N = 6
S.D = \(\sqrt{\frac{(x - x)^2}{N}}\)
S.D = \(\sqrt{\frac{150}{6}}\) = 5
50 tan 30o
50 sin 54o
50 tan 54o
50 sin 36o
Correct answer is B
No explanation has been provided for this answer.
If cos(x + 40)o = 0.0872, what is the value of x?
85o
75o
65o
45o
Correct answer is D
cos(x + 40)o = 0.0872
x + 40 = cos-10.0872
x + 40o = 84.99o
x = 84.99o - 40o
x = 44.99
x = 45o
In \(\bigtriangleup\) XYZ, /XY/ = 8cm, /YZ/ = 10cm and /XZ/ = 6cm. Which of these relation is true?
/XY/ + /YZ/ = /XZ/
/XY/ - /YZ/ = /XZ/
/XY/2 = /Y/2 - /XY/2
/YZ/2 = /XZ/2 + /XY/2
Correct answer is D
No explanation has been provided for this answer.