750N
745N
735N
98N
Correct answer is C
Net force = Upward force - weight
\(ma = F - mg\)
With constant velocity, acceleration = 0, therefore, ma = 0
\(\therefore F = mg = 75 \times 9.8 = 735N\).
| Marks | 0 | 1 | 2 | 3 | 4 | 5 |
| Number of candidates | 6 | 4 | 8 | 10 | 9 |
3 |
The table above shows the distribution of marks scored by students in a test. Find the interquartile range of the distribution.
4
3
2
1
Correct answer is B
No explanation has been provided for this answer.
| Marks | 0 | 1 | 2 | 3 | 4 | 5 |
| Number of candidates | 6 | 4 | 8 | 10 | 9 | 3 |
The table above shows the distribution of marks scored by students in a test. How many candidates scored above the median score?
3
12
22
30
Correct answer is B
The total number of candidates = 40, therefore, the median occurs as the average between the 20th and 21st candidates. = \(\frac{3+3}{2} = 3\)
Number of candidates that scored above 3 : 9 + 3 = 12.
\(\sqrt{15}\)
4
\(\sqrt{24}\)
\(\sqrt{26}\)
Correct answer is D
\(r = 2i - j , s = 3i + 5j , t = 6i - 2j\)
\(2r + s - t = 2(2i - j) + (3i + 5j) - (6i - 2j) = i + 5j\)
\(|2r + s - t| = \sqrt{1^{2} + 5^{2}} = \sqrt{26}\)
\(p \vee q\)
\(\sim p \vee q\)
\(p \wedge (\sim q)\)
\( p \wedge q\)
Correct answer is D
No explanation has been provided for this answer.