WAEC Mathematics Past Questions & Answers - Page 127

631.

\(\begin{array}{c|c} x & 0 & 2 & 4 & 6\\ \hline y & 1 & 2 & 3 & 4\end{array}\).
The table is for the relation y = mx + c where m and c are constants. What is the equation of the line described in the tablet?

A.

y = 2x

B.

y = x + 1

C.

y = x

D.

y = \(\frac{1}{2}x + 1\)

Correct answer is D

y = mx + c; when x = 0; y = 1

1 = m(0) + c; 1 = 0 + c; c = 1

when x = 2; y = 2

2 = m(2) + c; 2 = 2m + c; but c = 1

2 = 2m + 1

2 - 1 = 2m

2m = 1

m = \(\frac{1}{2}\)

y = \(\frac{1}{2}\)x + 1

632.

The mean age of R men in a club is 50 years, Two men aged 55 and 63, left the club and the mean age reduced by 1 year. Find the value of R

A.

18

B.

20

C.

22

D.

28

Correct answer is B

mean age = \(\frac{\text{sum of ages}}{\text{no. of men}}\)

50 = \9\frac{sum}{R}\)

sum = 50R.....(1)

Sum of ages of the men that left = 55 + 63 = 188

remaining sum = 50R - 118

remaining no. of men = R - 2

now mean age = 50 - 1 = 49 years

49 = \(\frac{50R - 118}{R - 2}\)

49(R - 2) = 50R - 118

49R - 50R = -188 - 98

-R = -20

R = 20

633.

Bola sold an article for N6,900.00 and made a profit of 15%. If he sold it for N6,600.00 he would make a

A.

profit of 13%

B.

loss of 12%

C.

loss of 10%

D.

loss of 5%

Correct answer is C

s.p = N6900

%profit = 15%

%profit = \(\frac{s.p - c.p}{c.p}\) x 100%

15% = \(\frac{6900 - c.p}{c.p}\) x 100%

\(\frac{15}{100}\)c.p = N6900 - c.p

0.15 c.p = N6900 - c.p

1.15c.p + c.p = N6900

c.p = \(\frac{6900}{1.15}\)

= 6000.00

Now new S.P = N6600

profit = s.p - c.p = 6000 - 6600

= 600

%profit = \(\frac{600}{6600}\) x 100%

= 10%

634.

How many times, correct to the nearest whole number, will a man run round circular track of diameter 100m to cover a distance of 1000m?

A.

3

B.

4

C.

5

D.

6

Correct answer is A

No. of times = \(\frac{\text{Total distance}}{\text{Circumference of circle}}\)

= \(\frac{\text{Total distance}}{\pi d}\)

= \(\frac{1000m}{\frac{22}{7} \times 100m}\)

= \(\frac{1000 \times 7}{2200} = 3.187\)

= 3(approx.) nearest whole no.

635.

The nth term of the sequence -2, 4, -8, 16.... is given by

A.

Tn = 2n

B.

Tn = (-2)n

C.

Tn = (-2n)

D.

Tn = n

Correct answer is B

sequence: -2, 4, -8, 16........{GP}

a = -2; r = \(\frac{4}{-2}\) = -2

nth term Tn = arn-1

Tn = (-2)(-2)^n-1

Tn = (-2)1 + n - 1

Tn = (-2)n