1.44 x 10-7N
7.20 x 10-9N
7.20 x 10-11N
1.44 x 1011N
Correct answer is A
f = \(\frac{1}{4 \pi \mathit{E}_o} \times \frac{Q^2}{r^2} = \frac{9 \times 10^9(2 \times 10^{-2})^2}{(0.05)^2}\)
= 1.44 x 10-2N
be negatively charged
be positively charged
have an excess negatively charges on the side nearest the rod
have an excess positively charges on the side nearest the rod
Correct answer is D
No explanation has been provided for this answer.
d = \(\frac{2t}{\lambda}\)
d = \(\frac{\lambda t}{2T}\)
d = \(\frac{2T}{\lambda t}\)
d = \(\frac{\lambda T}{2t}\)
Correct answer is B
V = \(\frac{2d}{t}\)
f\(\lambda = \frac{2d}{t} = \frac{\lambda}{T} = \frac{2d}{t}\)
Which of the following defects of vision is as a result of the eye ball being too long?
long sight
astigmatism
short sight
loss of accommodation
Correct answer is C
No explanation has been provided for this answer.
1 cm
9cm
12cm
15cm
Correct answer is B
\(\frac{v}{u} = \frac{hi}{ho} = \frac{60}{20} = \frac{hi}{3}\)
hi = 9cm