In the diagram, /TP/ = 12cm and it is 6cm from O, the centre of the circle, Calculate < TOP
120o
90o
60o
45o
Correct answer is B
Tan \(\theta = \frac{6}{6} = 1\)
\(\theta\) = tab - 1(1) = 45o
< top = 20
= 2 x 45o = 90o
27cm2
30cm2
36cm2
37cm2
Correct answer is A
Area = \(\frac{1}{2}(a + b)\)h
where a = QR = 6cm
b = PA = 10cm
Area = \(\frac{1}{2}(6 + 10)\) x 3.35cm2
= \(\frac{1}{2}(16)\) x 3.35cm2
= 26.8cm2
= 27cm2 (approx.)
3.35cm
3.73cm
4.50cm
4.62cm
Correct answer is A
h = ?
\(\frac{h}{5cm}\) = sin 45o
h = 5cm x 0.6691 = 3.35cm
The following is the graph of a quadratic friction, find the value of x when y = 0
1, 2
1, 4
2, 3
1, 6
Correct answer is B
when y = 0, value of x = roots of the equation
x2 - 5x + 4 = 0
x = 1, 4 (see graph)
The following is the graph of a quadratic friction, find the co-ordinates of point P
(0, 4)
(4, 0)
(0, -4)
(-4, 0)
Correct answer is A
No explanation has been provided for this answer.
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