Calculate the effective resistance between P and Q in the diagram above
0.75\(\Omega\)
4.00\(\Omega\)
5.00\(\Omega\)
7.00\(\Omega\)
Correct answer is B
R = \(\frac{1}{2} + \frac{1}{2} + 3 = 1 + 3 = 4\Omega\)
10.5N
11.0N
17.3N
20.0N
Correct answer is D
10 - P sin 30 = 0
10 - P x 0.5 = 0
P = 20N
it is very hot at the equator
the spring balance has expanded
the acceleration of free fall due to gravity varies with location
the mass of the body is reduced
Correct answer is C
No explanation has been provided for this answer.
100Nm-2
200Nm-2
300Nm-2
400Nm-2
Correct answer is A
P = \(\frac{wt}{A} = \frac{200}{2 \times 1} = 100Nm^{-2}\)
18kW
20kW
180kW
200kW
Correct answer is A
P = FV
= 600 x 30 = 18kW