What is the median of the following scores: 22 35 41 63 74 82
82
52
49
22
Correct answer is B
22 35 41 63 74 82
Median = \(\frac{41 + 63}{2} = \frac{104}{2}\)
= 52
40
45
55
60
Correct answer is B
\(\frac{x + 50 + 70}{3} = 55\)
x + 120 = 3(55)
x + 120 = 165
= 165 - 120
x = 45%
\(\frac{2 + \sqrt{3}}{3}\)
\(\frac{1 - \sqrt{3}}{3}\)
\(\frac{1 + \sqrt{3}}{3}\)
\(\frac{2 - \sqrt{3}}{3}\)
Correct answer is D
Sin 60 = \(\frac{\sqrt{3}}{2}\); cos 60o = \(\frac{1}{2}\)
= \(\frac{1 - \sin 60}{1 + \cos 60} = \frac{1 - \frac{\sqrt{3}}{2}}{1 + \frac{1}{2}}\)
= \(\frac{2 - \sqrt{3}}{3}{2}\div \frac{2 + 1}{2}\)
= \(\frac{2 - \sqrt{3}}{2} \times \frac{2}{3}\)
= \(\frac{2 - \sqrt{3}}{3}\)
If M and N are two fixed points in a plane. Find the locus L = [P : PM = PN]
a line equal to MN
line parallel to MN
Perpendicular bisector of MN
A circle centre P, radius MN
Correct answer is C
Locus L = (P : PM = Pn}
For M and N being two fixed points
Since PM = PN, P is equidistant from Mand N, So L must be the perpendicular bisector of the line MN
80o
70o
65o
40o
Correct answer is C
(2x + 5)o + (xo + 20o) + x + (3x - 20)o + (x + 15)o = (n - 2) x 180
8n + 20 = (5 - 2) x 180
where n = 5(Pentagon)
8n + 20 = 3 x 180
8n + 20 = 540
8n = 540 - 20
8n = 520
x = 65o