WAEC Chemistry Past Questions & Answers - Page 14

66.

What is the percentage composition of carbon
in Ca(HCO3)\(_{2}\) ?
[ Ca = 40.0, 0= 16.0, C = 12.0, H= 1.0]

A.

22.2%

B.

14.8%

C.

7.4%

D.

3.7%

Correct answer is B

. % of C in Ca(HCO3)2
Molar mass of Ca(HCO3)2 = 40+(1+12+(16*3))2
=40+(13+48)2
=40+122
=162
C/Ca(HCO3)2 x 100
=12 * 2/162 * 100
=14.8%

67.

Which of the following elements would displace copper from a solution of copper ions?

A.

silver

B.

gold

C.

lead

D.

mercury

Correct answer is C

The reactivity series allows us to predict how metals react. A more reactive metal displaces a less reactive metal from a compound. Lead is more reactive metal than copper hence, copper is displaced from copper solution by lead.

68.

If 50 cm\(^{3}\) of a saturated solution of KNO\(_{3}\) at 40 °C contained 5.05 g of the salt, its solubility at the same temperature would be
[KNO\(_{3}\) = 101]

A.

1.0 mol dm\(^{-3}\)

B.

1.5 mol dm\(^{-3}\)

C.

2.0 mol dm\(^{-3}\)

D.

5.0 mol dm\(^{-3}\)

Correct answer is A

V= 50cm\(^{3}\)
Mass= 5.05g
Relative molecular mass of KNO\(_{3}\) = (39+14+(3*16)) = 101
Convert 50cm\(^{3}\) to dm\(^{3}\) which is
1000cm³ = 1dm\(^{3}\)
50cm³ = 50*1/1000
= 0.05dm\(^{3}\)
Moles = mass/ molar mass
= 5.05/101 =0.05mole
Solubility= mole/volume
Solubility=0.05mol/0.05dm\(^{3}\)
Solubility=1.0mol/dm_\(^{3}\)

69.

What number of moles of oxygen would exert a pressure of 10 atm at 320 K in an 8.2 dm\(^{3}\) cylinder?
[R=0.082 atm dm\(^{-3}\) mol\(^{-1}\) K\(^{-1}\)]

A.

0.32

B.

1.52

C.

3.13

D.

31.25

Correct answer is C

P = 10atm, T= 320K, V= 8.2dm\(^{3}\)
PV =nRT
n = P * V/R * T
10 * 8.2/0.082 * 320
= 82/26.24
n = 3.13

70.

A hydrogen chloride gas reacted with oxygen gas to yield water and chlorine gas. The mole ratio of the hydrogen chloride gas to water is

A.

1:3

B.

2:1

C.

3:1

D.

4:1

Correct answer is B

4HCl + O\(_{2}\) -- 2Cl\(_{2}\) + 2H\(_{2}\)O
4:2 = 4/2
2:1