Study the table below and use it to answer the question
| Cost Price (N) | Useful Life (Life) | Salvage value (N) | Annual depreciation (N) | Total depreciation |
| 20000 | Y | 5000 | 1000 annum | 15000 |
| 60000 | 10 | 18000 | 4200 annum | Z |
The useful life represented by Y in the illustrated table is
3 years
4 years
15 years
20 years
Correct answer is C
Cost Price (N) = 20000
Salvage value (N) = 5000
Annual depreciation (N) = 1000
Total depreciation = 15000
The formula to calculate the useful life is:
Useful life = (Cost Price - Salvage value) / Annual depreciation
Now, let's plug in the values:
Useful life = (20000 - 5000) / 1000
Useful life = 15000 / 1000
Useful life = 15 years
Therefore, the useful life represented by Y in the table is 15 years.
\(\frac{[NO^2]}{[N^2] + [O^2]}\)
\(\frac{[2NO]^2}{[N_2][O_2]}\)
\(\frac{[N_2] + [O_2]}{2[NO]^2}\)
\(\frac{[NO]^2}{[N_2][O^2]}\)
Correct answer is D
No explanation has been provided for this answer.
the yield of XY 3 will decompose
more of XY3 will decompose
More of X2 will react
the forward reaction will remain static
Correct answer is C
Increase in temperature will cause the forward reaction to occur, increasing the amounts of the products and decreasing the amounts of reactants.
Nitrobacter
Rhizobium
Nitrosomonas
Azotobacter
Correct answer is B
Nitrosomonas is the bacterium responsible for the first step in this conversion process, where it oxidizes ammonium compounds to nitrites. This conversion is essential as it prepares the nitrogen compounds for the subsequent steps in the nitrogen cycle.
Calculate the mass of sodium hydroxide in 5.00 dm3 of a 0.125 mol dm-3 solution. [NaOH = 40 g mol-1]
0.0156 g
0.625 g
1.00 g
25.0 g
Correct answer is D
1 mole of NaOH per dm3 has a mass of 40g.
mass of NaOH in 0.125mole
= 0.125 x 40 = 5g.
mass in 5.00 dm3 of the solution.
= 5 x 5 = 25.0g.