240.0N
800.0N
1600.00N
2400.0N
Correct answer is A
S = at + \(\frac{1}{2} at^2\)
60 = 0 x 20 + \(\frac{1}{2}\) x a x 20
a = \(\frac{3}{10}\)m/s2
F = ma = 800 x \(\frac{3}{10} = 240N\)
50ms-1
25ms-1
20ms-1
5ms-1
Correct answer is C
a = \(\frac{F}{m} = \frac{100}{0.15} = 666.7\)
v = u + at
= 0 + 66.7 x 0.03
= 20m/s2
10\(\sqrt 5\) rads-1
5\(\sqrt 2\) rads-1
5 rads-1
\(\sqrt 5\) rads-1
Correct answer is A
K = \(\frac{F}{e} = \frac{4}{0.16} = 250\)
F = \(\frac{1}{T} = \frac{1}{2 \pi \frac{\sqrt{m}}{k}}\)
= \(\frac{1}{2 pi \frac{\sqrt{0.5}}{250}}\)
= 10\(\sqrt{5}\)
A swinging pendulum between the rest position and its maximum displacement possesses
Kinetic energy only
potential energy only
gravitational energy only
both kinetic and potential energy
Correct answer is D
No explanation has been provided for this answer.
4.5 ms-1
6.0ms-1
18.0-1
36.0-1
Correct answer is B
v = \(\sqrt{U^2} + 2as = \sqrt{0^2} + 2 \times 2 \times 9 = 6\)m/s