\(\frac{R}{5}\)
-\(\frac{R}{4}\)
\(\frac{5R}{36}\)
\(\frac{-5R}{36}\)
Correct answer is C
Given that W = -\(\frac{R}{n^2}\)
from n = 3 to n = 2.
-\(\frac{R}{3^2}\) - (-\(\frac{R}{2^2}\))
-\(\frac{R}{9}\) - (-\(\frac{R}{4}\))
-\(\frac{R}{9}\) + \(\frac{R}{4}\);
with LCM 36
\(\frac{-4R + 9R}{36}\)
= \(\frac{5R}{36}\)
Calculate the inductance L, of the coil in the circuit diagram shown above
3.8H
0.6H
0.4H
0.2H
Correct answer is B
XL = \(\frac{V}{I} = \frac{240}{2} = 120\Omega\)
L = \(\frac{X_L}{2 \pi f}\)
= \(\frac{120 \times \pi}{2 \times \pi \times 100}\)
= 0.6H
north-south
south-west
north-east
south-east
Correct answer is A
No explanation has been provided for this answer.
85.0%
83.3%
37.5%
30.0%
Correct answer is B
No explanation has been provided for this answer.
strength of the magnet
number of turns in the coil
speed of location in the coil
gap between the poles of the magnet
Correct answer is D
No explanation has been provided for this answer.
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