WAEC Mathematics Past Questions & Answers - Page 197

981.

In\( ∆ PQR, P\hat{Q}P = 84^°, |Q\hat{P}R |= 43^°\) and |PQ| = 5cm. Find /QR/ in cm, correct to 1 decimal place.

A.

3.4

B.

4.3

C.

5.9

D.

6.2

Correct answer is B

Using the sine rule
\(\frac{|QR|}{sinP}=\frac{|PQ|}{sinR}\\
\frac{x}{sin43^o}=\frac{5}{sin53^o}\\
x = \frac{5\times sin43^o}{sin53^o}\\
=\frac{5\times 0.6820}{0.7986}\\
=4.3\)

982.

Find the value of x in the equation 3x\(^2\) - 8x - 3 = 0

A.

\(\frac{1}{3},-3\)

B.

\(-\frac{1}{3},-3\)

C.

\(-\frac{1}{3},3\)

D.

\(\frac{1}{3},3\)

Correct answer is C

3x\(^2\) - 8x - 3 = 0

3x\(^2\) - 9x + x - 3 = 0

3x(x - 3) + 1(x - 3) = 0

(3x + 1)(x - 3) = 0

3x = -1 \(\implies\) x = \(-\frac{1}{3}\)

or x = 3.

983.

In the diagram, ZM is a straight line. Calculate the value of x.

A.

27o

B.

30o

C.

35o

D.

37o

Correct answer is C

The sum of angles in a triangle is 180o
2xo + (2x -21)o + ∠ZYP = 180o
Also ∠ZYP = 180o - (3x+14)o
∴2xo + (2x-21)o + 180o - (3x+14)o = 180
x = 35o

984.

PQRS is a cyclic quadrilateral. If ∠QPS = 75°, what is the size of ∠QRS?

A.

180o

B.

150o

C.

105o

D.

75o

Correct answer is C

< QPS = 75°

< QRS = 180° - 75° = 105° (opposite angles of a cyclic quadrilateral)

985.

A pyramid of volume 120cm3 has a rectangular base which measures 5cm by 6cm. Calculate the height of the pyramid

A.

5cm

B.

9cm

C.

12cm

D.

15cm

Correct answer is C

\(V= \frac{1}{2}\hspace{1mm}base\hspace{1mm}area\hspace{1mm}\times\hspace{1mm}height\\
120=\frac{1}{3}\times 5 \times 6 \times h; h = \frac{120}{10}=12cm\)