WAEC Mathematics Past Questions & Answers - Page 203

1,011.

Factorize m(2a-b)-2n(b-2a)

A.

(2a-b)(2n-m)

B.

(2a+b)(m-2n)

C.

(2a-b)(m+2n)

D.

(2a-b)(m-2n)

Correct answer is C

m(2a - b) - 2n(b - 2a)

= m(2a - b) - (-2n)(2a - b)

= m(2a - b) + 2n(2a - b)

= (m + 2n)(2a - b)

1,012.

Simplify \(3\sqrt{12} + 10\sqrt{3} - \frac{6}{\sqrt{3}}\)

A.

\(7\sqrt{3}\)

B.

\(10\sqrt{3}\)

C.

\(14\sqrt{3}\)

D.

\(18\sqrt{3}\)

Correct answer is C

\(3\sqrt{12} + 10\sqrt{3} - \frac{6}{\sqrt{3}}\)

= \(3(\sqrt{4 \times 3}) + 10\sqrt{3} - (\frac{6}{\sqrt{3}})(\frac{\sqrt{3}}{\sqrt{3}})\)

= \(6\sqrt{3} + 10\sqrt{3} - 2\sqrt{3}\)

= \(14\sqrt{3}\)

1,013.

The volume of a cylinder of radius 14cm is 210cm3. What is the curved surface area of the cylinder?

A.

15cm2

B.

30cm2

C.

616cm2

D.

1262cm2

Correct answer is B

\(V = \pi r^2 h\\
210 = \frac{22}{7} \times 14^2 \times h \\
h = \frac{210}{22 \times 28}\)
Curved surface area \(= 2r\pi h\\
= 2 \times \frac{22}{7} \times 14 \times \frac{210}{22 \times 26} = 30cm^2\)

1,014.

The angle of depression of a point Q from a vertical tower PR, 30m high, is 40°. If the foot P of the tower is on the same horizontal level as Q, find, correct to 2 decimal places, |PQ|.

A.

35.75m

B.

25.00m

C.

22.98m

D.

19.28

Correct answer is A

\(\tan 40° = \frac{30}{|PQ|}\)

\(|PQ| = \frac{30}{\tan 40°} = \frac{30}{0.839}\)

= 35.75m

1,015.

In the diagram, |SR| = |RQ| and ∠PRQ = 58o ∠VQT = 19o, PQT, SQV and PSR are straight lines. Find ∠QPS

A.

42o

B.

39o

C.

38o

D.

30o

Correct answer is A

No explanation has been provided for this answer.