3.00 x 108ms-1
2.46 x 108ms-1
1.57 x 108ms-1
1.32 x 108ms-1
1.11 x 108ms-1
Correct answer is C
ev = \(\frac{1}{2}\)mv2
v2 = \(\frac{ev}{\frac{1}{2}m}\)
V = \(\sqrt{\frac{ev}{\frac{1}{2m}}} = \sqrt{\frac{1.6 \times 10^{-19} \times 70 \times 10^3}{\frac{1}{2} \times 9.1 \times 10^{-31}}}\)
= \(\sqrt{246.2 \times 10^{14}}\) = 1.57 x 108
Which of the following explains the concave meniscus of water in a clean glass tube? the
adhension between water and glass molecules is greater than the sdhension between water molecules
cohension between water molecules is greater then the adhension between glass and water molecule
molecules of water near the glass move faster than the molecules at the centre of the tube
molecules of water at the water-air boundary are often attracted to the centre of the tube
weight of the water pulls the centre part of the surface down
Correct answer is A
No explanation has been provided for this answer.
3.0mm
3.5mm
503.00mm
503.5mm
506.0mm
Correct answer is C
F \(\alpha\) e
F = ke
K = \(\frac{F}{e} = \frac{5}{0.5} = 10\)
when F = 30, e = \(\frac{F}{K} = \frac{30}{10} = 3\)
L = 500 + 3 = 503.00
1.33
1.25
0.80
0.75
0.60
Correct answer is C
cos\(\theta = \frac{R}{Z}\)
R = \(\frac{V}{I} = \frac{40}{2} = 20\)
Z² = R² + \(^X_L\)² = 20² + 15² = √625 = 25
cos \(\theta = \frac{R}{Z} = \frac{20}{25} = 0.8\)
The direction of the magnetic field at a point in the vicinity of a bar magnetic is
along the line joining the point to the neutral point
always away from the south pole of the magnet
opposite the direction of the resultant field at that point
always towards the north pole of the magnet
the direction towards which the north pole of a compass needle would point
Correct answer is E
No explanation has been provided for this answer.
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