WAEC Chemistry Past Questions & Answers - Page 235

1,171.

The loss of molecules of water of crystallization to the atmosphere by some crystalline salts is known as

A.

efflorescence

B.

effervescence

C.

phosphorescence

D.

fluorescence

E.

deliquescence

Correct answer is A

No explanation has been provided for this answer.

1,172.

Which of the following is a general method of preparing acids?

A.

Direct combination of constituent elements

B.

Double decomposition involving a salt solution

C.

Reaction between an anhydride and water

D.

Reaction between a base and an amphoteric oxide

E.

Dissolution of hydroxides followed by neutralization

Correct answer is C

There are several methods of preparation of acids. These include the following:

1. By the reaction between an acidic oxide of a non-metal (acid anhydride) and water.

SO2(g) + H2O(l) → H2SO3(aq) Trioxosulphate(IV)

P4010(s) + 2H2O(l) → 4HPO3(aq) Trioxophosphate(V)

1,173.

An acid is a substance which in the presence of water produces

A.

salts

B.

oxygen

C.

effervescence

D.

hydroxonium ions

E.

hydrogen gas

Correct answer is D

No explanation has been provided for this answer.

1,174.

A given volume of methane diffuses in 20 seconds. How long will it take the same volume of sulphur (IV) oxide to diffuse under the same conditions? [CH4 = 16; SO2 = 64]

A.

5 seconds

B.

20 seconds

C.

40 seconds

D.

60 seconds

E.

80 seconds

Correct answer is C

Applying the Graham's law defination; i.e,

\(\frac{R(SO_2)}{R(CH_4)} = \sqrt{\frac{M(CH_4)}{M(SO_2)}} = \frac{t(CH_4)}{t(SO_2)}\)

Where t(SO\(_2\)) = ?, M(SO\(_2\)) = 64

t(Ch\(_4\)) = 20 sec, M(Ch\(_4\)) = 16

therefore, \(\frac{t(SO_2)}{20}\) = \(\sqrt{\frac{64}{16}}\)

\(\frac{t(SO_2)}{20}\) = \(\frac{8}{4}\)

t(SO\(_2\)) = 8 x \(\frac{20}{4}\)

= 40 sec.

1,175.

An increase in the pressure of a gas results in a decrease in its

A.

mass

B.

vapour density

C.

volume

D.

temperature

E.

concentration

Correct answer is C

No explanation has been provided for this answer.