\(\frac{1}{6}\)
\(\frac{1}{4}\)
\(\frac{1}{3}\)
\(\frac{1}{2}\)
Correct answer is C
Pr(green) = \(\frac{6}{5 + 6 + 7}\)
= \(\frac{6}{18}\)
= \(\frac{1}{3}\)
In the diagram, PQ is parallel to RS, < QFG = 105\(^o\) and < FEG = 50\(^o\). Find the value of n
40\(^o\)
55\(^o\)
75\(^o\)
130\(^o\)
Correct answer is C
E\(G\)R = 50\(^o\) (Alternative angles)
n + 55\(^o\) + 50\(^o\) = 180\(^o\) (Sum of angles on a straight line)
n = 180\(^o\) - 105\(^o\)
n = 75\(^o\)
In the diagram, PQ is parallel to RS, < QFG = 105\(^o\) and < FEG = 50\(^o\). Find the value of m.
130\(^o\)
105\(^o\)
75\(^o\)
55\(^o\)
Correct answer is D
50\(^o\) + m = 105\(^o\) (exterior angle of \(\triangle\)
m = 105\(^o\) - 50\(^o\)
m = 55\(^o\)
7.2
6.8
3.5
2.6
Correct answer is B
|
x 2 4 7 8 9 |
(\(\bar{x} - \bar{x}\)) -4 -2 1 2 4 |
(\(\bar{x} - \bar{x})^2\) 16 4 1 4 9 _________ \(\sum (x - x)^2\) = 34 |
\(\bar{x} = \frac{2 + 4 + 7 + 8 + 9}{5} = 6
variance = \(\frac{34}{5}\)
= 6.8
70\(^o\)
58\(^o\)
55\(^o\)
48\(^o\)
Correct answer is B
x = 180\(^o\) - (52\(^o\) + 70\(^o\))
= 180\(o\) - 122\(^o\)
= 58\(^o\)
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