20km
24km
25km
31km
84km
Correct answer is C
No explanation has been provided for this answer.
If sin x = cos 50o, then x equals
40o
45o
50o
90o
130o
Correct answer is A
No explanation has been provided for this answer.
120km
165km
195km
(150 + 45√3)km
240km
Correct answer is C
No explanation has been provided for this answer.
State the fifth and seventh terms of the sequence \(-2, -3, -4\frac{1}{2}, ...\)
\(-\frac{81}{8}, -\frac{729}{32}\)
\(\frac{8}{81}, \frac{72}{39}\)
\(\frac{27}{729}, \frac{718}{39}\)
\(-\frac{27}{16}, -\frac{79}{81}\)
\(-\frac{21}{8}, \frac{32}{618}\)
Correct answer is A
\(-2, -3, -4\frac{1}{2}, ...\)
This is a G.P with r = 1\(\frac{1}{2}\).
\(T_{n} = ar^{n - 1}\) (terms of a G.P)
\(T_{5} = (-2)(\frac{3}{2})^{5 - 1}\)
= \(-2 \times \frac{81}{16}\)
= \(-\frac{81}{8}\)
\(T_{7} = (-2)(\frac{3}{2})^{7 - 1}\)
= \(-2 \times \frac{729}{64}\)
= \(-\frac{729}{32}\)
Simplify \(\frac{2.25}{0.015}\) leaving your answer in standard form
1.5 x 10-4
1.5 x 10-2
1.5 x 10-3
1.5 x 101
1.5 x 102
Correct answer is E
\(\frac{2.25}{0.015}\)
= \(\frac{2250}{15}\)
= \(150\)
= \(1.5 \times 10^{2}\)