WAEC Past Questions and Answers - Page 2998

14,986.

If 92x = \(\frac{1}{3}\)(27x), find x

A.

2

B.

1

C.

-1

D.

-2

Correct answer is C

92x = \(\frac{1}{3}\)(27x)

(22)2x = \(\frac{(3^{3x})}{3}\)

(34x) = 33x - 1

4x = 3x - 1

4x - 3x = -1

x = -1

14,987.

Express 2.7864 x 10-3 to 2 significant figures

A.

0.28

B.

0.27

C.

0.0028

D.

0.0027

Correct answer is C

2.7864 x 10-3 = 0.0027864

= 0.0028(approx. 2 s.f)

14,988.

What is the median of the following scores: 22 35 41 63 74 82

A.

82

B.

52

C.

49

D.

22

Correct answer is B

22 35 41 63 74 82


Median = \(\frac{41 + 63}{2} = \frac{104}{2}\)

= 52

14,989.

In an examination, Kofi scored x% in Physics, 50% in Chemistry and 70% in Biology. If his mean score for the three subjects was 55%, find x

A.

40

B.

45

C.

55

D.

60

Correct answer is B

\(\frac{x + 50 + 70}{3} = 55\)

x + 120 = 3(55)

x + 120 = 165

= 165 - 120

x = 45%

14,990.

Given that sin 60o = \(\frac{\sqrt{3}}{2}\) and cos 60o = \(\frac{1}{2}\), evaluate \(\frac{1 - sin 60^o}{1 + cos 60^o}\)

A.

\(\frac{2 + \sqrt{3}}{3}\)

B.

\(\frac{1 - \sqrt{3}}{3}\)

C.

\(\frac{1 + \sqrt{3}}{3}\)

D.

\(\frac{2 - \sqrt{3}}{3}\)

Correct answer is D

Sin 60 = \(\frac{\sqrt{3}}{2}\); cos 60o = \(\frac{1}{2}\)

= \(\frac{1 - \sin 60}{1 + \cos 60} = \frac{1 - \frac{\sqrt{3}}{2}}{1 + \frac{1}{2}}\)

= \(\frac{2 - \sqrt{3}}{3}{2}\div \frac{2 + 1}{2}\)

= \(\frac{2 - \sqrt{3}}{2} \times \frac{2}{3}\)

= \(\frac{2 - \sqrt{3}}{3}\)