\(\frac{3}{4}\)
\(\frac{1}{2}\)
\(\frac{1}{3}\)
\(\frac{1}{4}\)
Correct answer is D
No. of red = 5
No. of blue = 4
No. of green = 3
Total = 12
Pr(Green) = \(\frac{3}{12} = \frac{1}{4}\)
Find the sum of the interior angle of a pentagon.
340\(^o\)
350\(^o\)
540\(^o\)
550\(^o\)
Correct answer is C
Sum = (5 - ) 180\(^o\)
= (5 - 2) 180\(^o\) = 3 x 180\(^o\)
= 540\(^o\)
The mean of the numbers 15, 21, 17, 26, 18, and 29 is 21. Calculate the standard deviation
9
6
5
0
Correct answer is C
|
x |
x - \(\overline{x}\))\(^2\) | (x - \(\overline{x}\))\(^2\) |
|
15 21 17 26 18 29 |
-6 0 -4 5 -3 -8 |
36 0 16 25 9 64 |
| \(\sum (x - \overline{x})^2\) = 150 |
Standard deviation = \(\sqrt{\frac{ \sum (x - \overline{x})^2}{n} }\)
= \(\frac{150}{6}\)
= \(\sqrt{25}\)
= 5
845,000
600,000
355,000
250,000
Correct answer is C
Angle of Men = 360\(^o\) - (120 + 169)
= 360\(^o\) - 289\(^o\) = 71\(^o\)
No. of men \(\frac{71}{360}\) x 1800,000
= 355,000
In the diagram, PQR is a circle with center O. If ∠OPQ = 48°, find the value of M.
96\(^o\)
90\(^o\)
68\(^o\)
42\(^o\)
Correct answer is A
< O\(Q\)P = 48\(^o\) (base angles of isoceles \(\triangle\))
m = 48\(^o\) + 48\(^o\) = 96\(^o\) (exterior angle of a \(\triangle\))
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