WAEC Past Questions and Answers - Page 3285

16,421.

The derived unit of pressure can be expressed as

A.

kgms-2

B.

kg m-1s-2

C.

kg m-2s-2

D.

kg m-1s2

Correct answer is B

Pressure = \(\frac{Force}{Area}\)

Force = mass x acceleration

\(\therefore\) Pressure = \(\frac{mass \times acceleration}{Area}\)

= \(\frac{kg \times m \times s^{-2}}{m^2}\)

= kg m\(^{-1}\) s\(^{-2}\)

16,422.

Using the circuit diagram above. Calculate the potential difference across the capacitors in parallel

A.

10.0V

B.

8.0V

C.

6.7V

D.

2.0V

Correct answer is D

V = \(\frac{Q}{V} = \frac{16}{8} = 2\Gamma\)

16,423.

Using the circuit diagram above. Calculate the total charge in the circuit

A.

80\(\mu C\)

B.

35\(\mu C\)

C.

20\(\mu C\)

D.

16\(\mu C\)

Correct answer is D

C - \(C_1 + C_2 = 2 + 6 = \mu F\)

\(\frac{1}{C} = \frac{1}{C_1} + \frac{1}{C_1} + \frac{1}{C_2} = \frac{1}{8} + \frac{1}{2}\)

C = \(\frac{8}{5 \mu F}\)

Q = CV

= \(\frac{8}{5} \times 10 = 16\mu C\)

16,424.

Nuclear fusion is not used as a source of enegy because

A.

very high temperature is needed for the reaction

B.

the fuel for the reaction is not easy to obtain

C.

less energy is released

D.

the reaction is too slow

Correct answer is A

No explanation has been provided for this answer.

16,425.

The change in mass of fuel during a nuclear reaction is 2.0 x 10-27 kg. Calculate the amount of energy released. (Speed of light = 2.0 x 108ms-1)

A.

1.8 x 10-10J

B.

9.0 x 10-11J

C.

6.0 x 10-19J

D.

1.2 x 10-45J

Correct answer is A

Q = \(\Delta MC^2\)

= 2 x 10-27(3 x 10)2

= 1.8 x 10-10J