1:00 pm
12:00 noon
11:00 am
10:00 am
Correct answer is C
Let x be the time
Then 72x + 48x = 240
\(\frac{120}{120} \times \frac{240}{120}\)
x = 2hrs
9:00 + 2hrs = 11:00 am
x = \(\frac{6y}{z}\)
x = \(\frac{12y}{z}\)
x = \(\frac{3y}{z}\)
x = \(\frac{3y}{2z}\)
Correct answer is A
\(x\) x \(\frac{y}{z}\)
x = \(\frac{ky}{z}\)
15 = \(\frac{10k}{4}\)
\(\frac{60}{10}\) = k = 6
Therefore; x = \(\frac{6y}{z}\)
Find the quadratic equation whose roots are \(\frac{1}{2}\) and -\(\frac{1}{3}\)
3x\(^2\) + x + 1 = 0
6x\(^2\) + x - 1 = 0
3x\(^2\) + x - 1 = 0
6x\(^2\) - x - 1 = 0
Correct answer is D
x = \(\frac{1}{2}\) and x = \(\frac{-1}{3}\)
(2x - 1) = 0 and (3x + 1) = 0
(2x - 1) (3x + 1) = 0
6x\(^2\) - x - 1 = 0
Make m the subject of the relation k = \(\frac{m - y}{m + 1}\)
m = \(\frac{y + k^2}{k^2 + 1}\)
m = \(\frac{y + k^2}{1 - k^2}\)
m = \(\frac{y - k^2}{k^2 + 1}\)
m = \(\frac{y - k^2}{1 - k^2}\)
Correct answer is B
k = \(\frac{m - y}{m + 1}\)
k\(^2\) = \(\frac{m - y}{m + 1}\)
k\(^2\)m + k\(^2\) = m - y
k\(^2\) + y = m - k\(^2\)m
\(\frac{k^2 + y}{1 - k^2}\) = m\(\frac{(1 - k^2)}{1 - k^2}\)
m = \(\frac{y + k^2}{1 - k^2}\)
Solve \(\frac{1}{3}\)(5 - 3x) < \(\frac{2}{5}\)(3 - 7x)
x > \(\frac{7}{22}\)
x < \(\frac{7}{22}\)
x > \(\frac{-7}{27}\)
x < \(\frac{-7}{27}\)
Correct answer is D
\(\frac{1}{3}\)(5 - 3x) < \(\frac{2}{5}\)(3 - 7x)
5(5 - 3x) < 6(3 - 7x)
25 - 15x < 18 - 42x
- 15x + 42x < 18 - 25
\(\frac{27x}{27}\) < \(\frac{-7}{27}\)
x < \(\frac{-7}{27}\)