120m
138m
274m
1200m
120,000m
Correct answer is D
pressure change for air = pressure change for mercury
hpg = Hpg
h x 0.00136 x g = (75 - 63) x 13.6 x g
h = \(\frac{12 \times 13.6}{0.00136}\)
= 120,000cm
= 1,200m
PR/PQ
OR/PQ
OR/PR
PQ/PR
PQ/QR
Correct answer is E
No explanation has been provided for this answer.
sin\(\alpha\)
cos\(\alpha\)
tan\(\alpha\)
sec\(\alpha\)
cot\(\alpha\)
Correct answer is C
\(\mu = \frac{F}{R} = \frac{W sin \theta}{W cos q}\)
= tan\(\theta\)
As the end Q of the plank is raised, the component of W, normal to plank, will
increase
decrease
remain the same
be slightly greater than W
be independent of w
Correct answer is B
No explanation has been provided for this answer.
source of the radiation
intensity of the radiation
detection device for the electrons
amplitude of the radiation
frequency of the radiation
Correct answer is E
No explanation has been provided for this answer.
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