WAEC Past Questions and Answers - Page 3947

19,731.

Which of the following features of Paramecium is not an advancement over Amoeba? The possession of

A.

definite shape

B.

cilia

C.

oral groove

D.

nucleus

Correct answer is D

No explanation has been provided for this answer.

19,732.

In the diagram, PQST and QRST are parallelograms. Calculate the area of the trapezium PRST.

A.

60cm2

B.

50cm2

C.

40cm2

D.

30cm2

Correct answer is D

PR = 4 + 4 = 8 cm

Area of trapezium = \(\frac{1}{2} (a + b) h\)

= \(\frac{1}{2} (4 + 8) \times 5\)

= 30 cm\(^2\)

19,733.

A pole of length L leans against a vertical wall so that it makes an angle of 60o with the horizontal ground. If the top of the pole is 8m above the ground, calculate L.

A.

\(16\sqrt{3}m\)

B.

\(4\sqrt{3}m\)

C.

\(\frac{\sqrt{3}}{16}\)

D.

\(\frac{16\sqrt{3}}{3}\)

Correct answer is D

\(sin 60 = \frac{8}{L} = 8 \div \frac{\sqrt{3}}{2}; L = \frac{8}{sin 60}=\frac{16}{\sqrt{3}}\)
When we rationalize gives \(\frac{16\sqrt{3}}{3}\)

19,734.

The diagram shows the position of three ships A, B and C at sea. B is due north of C such that |AB| = |BC| and the bearing of B from A = 040°. What is the bearing of A from C

A.

040o

B.

070o

C.

110o

D.

290o

Correct answer is D

< ABC = 40° (alternate angles)

\(\therefore\) < ACB = \(\frac{180° - 40°}{2}\)

= 70°

\(\therefore\) Bearing of A from C = 360° - 70° 

= 290°

19,735.

From the diagram above. ABC is a triangle inscribed in a circle center O. ∠ACB = 40o and |AB| = x cm. calculate the radius of the circle.

A.

\(\frac{x}{sin 40^o}\)

B.

\(\frac{x}{cos 40^o}\)

C.

\(\frac{x}{2 sin 40^o}\)

D.

\(\frac{x}{2 cos 40^o}\)

Correct answer is C

No explanation has been provided for this answer.