WAEC Past Questions and Answers - Page 4083

20,411.

Factorize 2x\(^2\) - 21x + 45

A.

(2x - 9)(x - 5)

B.

(2x-15)(x + 3)

C.

(2x +15)(x - 3)

D.

(2x -15(x - 3)

E.

(2x - 9)(x + 5)

Correct answer is D

2x\(^2\) - 21x + 45

= 2x\(^2\) - 15x - 6x + 45

= x(2x - 15) - 3(2x - 15)

= (x - 3)(2x - 15)

20,412.

Using the diagram above, calculate the effective capacitance of the circuit

A.

1.56μf

B.

3.00μF

C.

3.71μF

D.

9.00μF

Correct answer is D

No explanation has been provided for this answer.

20,413.

Write as a single fraction: \(\frac{5}{6r} - \frac{3}{4r}\)

A.

r/12

B.

12/r

C.

1/6r

D.

r/6

E.

1/12r

Correct answer is E

\(\frac{5}{6r} - \frac{3}{4r}\)

= \(\frac{10 - 9}{12r}\)

= \(\frac{1}{12r}\)

20,414.

What is the difference between viviparous and oviparous animals?

A.

Possessing eggs with yolks

B.

Laying unfertilized eggs

C.

Possessing yolkless eggs

D.

Protecting eggs from predators

E.

Laying and brooding eggs

Correct answer is E

No explanation has been provided for this answer.

20,415.

Using the data on the diagram above, calculate the potential difference across the 20- Ω resistor. (Neglect the internal resistance of the cell)

A.

5V

B.

10V

C.

20V

D.

60V

Correct answer is D

Voltage across 5Ω resistor = IR = 2 × 5 = 10V
Since voltage in a parallel connection is the same, voltage across 10Ω is also 10V
Current flowing across the 10Ω resistor

I = V/R = 10/10

Current I= 1A


Total current flowing = 2 + 1 = 3A


Voltage across 20Ω resistor = IR

= 3 × 20

= 60V