WAEC Past Questions and Answers - Page 4249

21,241.

A group of students took a test and the following frequency table shows the scores above


The median score is

A.

o

B.

2.5

C.

3

D.

5

E.

7

Correct answer is C

There are 20 students. Hence, the median is found by the average of the 10th and 11th score.

= \(\frac{3 + 3}{2}\)

= 3

21,242.

A group of students took a test and the following frequency table shows the scores above


The mean score is

A.

1.75

B.

2

C.

2.5

D.

2.75

E.

3

Correct answer is D

Score 0 1 2 3 4 5 Total
Freq 2 3 4 2 7 2 20
\(fx\) 0 3 8 6 28 10 55

\(\bar{x} = \frac{\sum fx}{\sum f}\)

= \(\frac{55}{20}\)

= \(2.75\)

21,243.

A group of students took a test and the following frequency table shows the scores above
Find the mode

A.

2

B.

3

C.

4

D.

5

E.

7

Correct answer is C

The mode=4. It has the highest frequency of 7

21,244.

Find the 8th term of the A.P -3, -1, 1 ......

A.

13

B.

11

C.

-8

D.

-11

E.

-17

Correct answer is B

Un = a + (n-1)d
     = -3 + (8 - 1)2
     = 11

21,245.

Simplify 36\(^\frac{1}{2}\) x 64\(-^\frac{1}{3}\) x 5\(^0\)

A.

0

B.

1\24

C.

2/3

D.

11/2

E.

71/2

Correct answer is D

36\(^\frac{1}{2}\) x 64\(-^\frac{1}{3}\) x 5\(^0\)

= \(6 \times \frac{1}{4} \times 1\)

= \(1\frac{1}{2}\)