WAEC Physics Past Questions & Answers - Page 69

341.

What is the inductance (L) of an inductor whose reactance is 1Ω at 50/ π hertz (H)?

A.

100 H

B.

0.01H

C.

10H

D.

1H

Correct answer is B

XL = WL = 2πFL (w = 2πf)

XL = reactance inductor (S.I unit Ω)

L = inductance (L) in Henry

XL = 1Ω, f = 50/π, L = ?

1 = 2× π × 50/π × L

1 = 100L

i.e. 100L = 1

L = 1/100

0.01H

∴ Inductance (L) of a inductor = 0.01H

There is an explanation video available below.

342.

The direction of the path taken by light is called

A.

Locus

B.

Lines

C.

Ray

D.

Beam

Correct answer is C

Ray – a beam of light or radiation

There is an explanation video available below.

343.

Boyle’s law may be Written as

A.

P1V1= P2V2

B.

V1 = V2 ÷ T1T2

C.

P1T1 = P2T2

D.

P1V1 ÷ T1 = P1V1 ÷ T2

Correct answer is A

Boyle‘s law stats that the volume of a given mass of a gas, at a constant temperature is inversely proportional to us pressure.

Mathematically

V ∝ l/p, v = k/p (where k is constant)

K = VP

Let k = k1

Then, if k = k, V and P = V1P1

V1P1 = V2P2

There is an explanation video available below.

344.

If the volume of a gas is recorded as 76cm3 at a temperature of 27°C with a pressure of 800mmHg. What will be the volume of the gas at S.T.P?

A.

36.2cm3

B.

25.7cm3

C.

72.8cm3

D.

24.3cm3

Correct answer is C

General formular of Gas laws

(P1V1) ÷ T1= (P2V2) ÷ T2

P1 = 800mmHg, V, = 76cm3, Tr = 273 + 27 = 300k

P2 = 760mmHg, V2 = ? T2= 273 + 0 = 273  

(800 × 76) ÷ 300 = (760 × V2) ÷ 273

V2 = (300 × 76 × 273) ÷ (300 × 760) = 72.8 cm3

The volume of gas as S.T.P = 72.8 cm3

There is an explanation video available below.

345.

An element of nucleon number P and atomic number Q emits an alpha particle from its nucleus. The resultant numbers of the new element formed are respectively

A.

P - 4 and Q + 2

B.

P - 4 and Q - 2

C.

P + 2 and Q + 2

D.

P + 2 and Q - 2

Correct answer is B

No explanation has been provided for this answer.