70o
80o
105o
110o
Correct answer is B
In the diagram above, x1 = 50(angles in alternate segment)
x1 = x2(base angles of isos. \(\Delta\))
< UXY + x2 + 50o = 180o(sum of angles on a straight line)
< UXY + 50o + 50o = 180p
< UXY + 100o = 180o
< UXY = 180o - 100o
= 80o
13
14
15
16
Correct answer is B
Median = \(\frac{N}{2}\)th age
= \(\frac{50}{2}\)th age
= 25th age
= 14 years
50
55
60
65
Correct answer is A
Number of students in the club is
10 + 24 + 8 + 5 + 3 = 50
32o
40o
60o
69o
Correct answer is D
sin 60o = x + 0.5 0o(given)
0.8660 = x + 0.5
0.8660 - 0.5 = x
x = 0.3660
cos\(\theta\) = x(given)
cos\(\theta\) = 0.3660
Hence, \(\theta\) = cos-1(0.3660)
= 68.53o
= 69o (nearest degree)
A straight line passes through the point P(1,2) and Q
(5,8). Calculate the length PQ
\(4\sqrt{11}\)
\(4\sqrt{10}\)
\(2\sqrt{17}\)
\(2\sqrt{13}\)
Correct answer is D
|PQ| = \(\sqrt{(x_2 - X- 1) + (y_2 - y_1)^2}\)
= \(\sqrt{(5 - 1)^2 + (8 - 2)^2}\)
= \(\sqrt{4^2 + 6^2}\)
= \(\sqrt{16 + 36}\)
= \(\sqrt{52}\)
= 2\(\sqrt{13}\)
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