10\(sqrt{2}\)
4\(sqrt{5}\)
5\(sqrt{2}\)
2\(sqrt{5}\)
Correct answer is D
p(4, 3) Q(2 - 1)
distance = \(\sqrt{(x_2 - x_1)^2 + (Y_2 - y_1)^2}\)
= \(\sqrt{(2 - 4)^2 + (-1 - 3)^2}\)
= \(\sqrt{(-2)^2 = (-4)^2}\)
= \(\sqrt{4 + 16}\)
= \(\sqrt{20}\)
= \(\sqrt{4 \times 5}\)
= 2\(\sqrt{5}\)
Find the truth set of the equation x2 = 3(2x + 9)
{x : x = 3, x = 9}
{x : x = -3, x = -9}
{x : x = 3, x = -9}
{x : x = -3, x = 9}
Correct answer is D
x2 = 3(2x + 9)
x2 = 6x + 27
x2 - 6x - 27 = 0
x2 - 9x + 3x - 27 = 0
x(x - 9) + 3(x - 9) = (x + 3)(x - 9) = 0
x + 3 = 0 or x - 9 = 0
x = -3 or x = 9
x = -3, x = 9
{0, 2, 6}
{1, 3}
{0, 6)
{9}
Correct answer is C
x = {0, 2, 4, 6}; y = {1, 2, 3, 4}; z = {1, 3}
u = {0, 1, 2, 3, 4, 5, 6}
y' = {0, 5, 6}
to find x \(\cap\) (Y' \(\cup\) Z)
first find y' \(\cup\) z = {0, 1, 3, 5, 6}
then x \(\cap\) (Y' \(\cup\) Z) = {0, 6}
Three quarters of a number added to two and a half of the number gives 13. Find the number
4
5
6
7
Correct answer is A
let the number be x
2\(\frac{1}{2}x + \frac{3}{4}x = 13\)
\(\frac{5}{2}x + \frac{3}{4}x = 13\)
multiply through by 4
4(\(\frac{5}{2}\))x + 4(\(\frac{3}{4}\))x = 13 x 4
2(5x) + 3x = 52
10x + 3x = 52
13x = 52
x = \(\frac{52}{13}\)
x = 4
Given that x > y and 3 < y, which of the following is/are true? i. y > 3 ii. x < 3 iii. x > y > 3
i
i and ii
i and iii
i, ii and iii
Correct answer is C
x > y and 3 < y; then 3 < y means that y > 3 x > 3 to give the possible x > y > 3