Data Interpretation questions and answers

Data Interpretation Questions and Answers

Data Interpretation questions test one's ability in analysing data, inspecting the elements in data and interpreting them to extract maximum information from the given set of data or information. The data is usually given in the form of charts, tables and graphs.

Practise with our Data Interpretation questions and answers to help you know what to expect, improve your speed and confidence and be really prepared for the actual test.

76.

The following line graph gives the annual percent profit earned by a Company during the period 1995 - 2000.

Percent Profit Earned by a Company Over the Years.

%Profit = (Income - Expenditure)/Expenditure x 100

If the income in 1998 was Rs. 264 crores, what was the expenditure in 1998?

A.

Rs. 104 crores

B.

Rs. 145 crores

C.

Rs. 160 crores

D.

Rs. 185 crores

Correct answer is C

Let the expenditure is 1998 be Rs. x crores.

Then, 65 = ((264 - x)/x) x 100  

=>  65/100 = (264/x) - 1

=> x = (264 x100)/165 = 160.

Therefore Expenditure in 1998 = Rs. 160 crores.

77.

The following line graph gives the annual percent profit earned by a Company during the period 1995 - 2000.

Percent Profit Earned by a Company Over the Years.

%Profit = (Income - Expenditure)/Expenditure x 100

If the expenditures in 1996 and 1999 are equal, then the approximate ratio of the income in 1996 and 1999 respectively is?

A.

1:1

B.

2:3

C.

13:14

D.

9:10

Correct answer is D

Let the expenditure in 1996 = x.

Also, let the incomes in 1996 and 1999 be I1 and I2 respectively.

Then, for the year 1996, we have:

55 = (I1 - x)/x x 100   =>   55/100 = I1/x - 1  =>  I1 = 155x/100 ... (i)

70 = (I2 - x)/x x 100   =>   70/100 = I2/x - 1 => I2 = 170x/100 ... (ii)

From (i) and (ii), we get:

I1/I2 = (155x/100)/(170x/100) = 155/170 ≈ 0.91/1 ≈ 9 : 10

78.

The following line graph gives the percentage of the number of candidates who qualified for an examination out of the total number of candidates who appeared for the examination over a period of seven years from 1994 to 2000.

Percentage of Candidates who Qualified to Appeared in an Examination Over the Years

The total number of candidates who qualified in 1999 and 2000 together was 33500 and the number of candidates who appeared in 1999 was 26500. What was the number of candidates in 2000?

A.

24500

B.

22000

C.

20500

D.

19000

Correct answer is C

The number of candidates qualified in 1999 = (80% of 26500) = 21200.

Therefore Number of candidates qualified in 2000 = (33500 - 21200) = 12300.

Let the number of candidates appeared in 2000 be x.

Then, 60% of x = 12300   =>  x = ( (12300 x 100)/60 ) = 20500

79.

The following line graph gives the percentage of the number of candidates who qualified for an examination out of the total number of candidates who appeared for the examination over a period of seven years from 1994 to 2000.

Percentage of Candidates who Qualified to Appeared in an Examination Over the Years

If the total number of candidates who appeared in 1996 and 1997 together was 47400, then the total number of candidates who qualified in these two years together was?

A.

34700

B.

32100

C.

31500

D.

Data inadequate

Correct answer is D

The total number of candidates who qualified in 1996 and 1997 together, cannot be determined until we know at least, the number of candidates who appeared in any one of the two years 1996 or 1997 or the percentage of candidates who qualified to candidates who appeared in 1996 and 1997 together.

Hence, the data is inadequate.

80.

The following line graph gives the percentage of the number of candidates who qualified for an examination out of the total number of candidates who appeared for the examination over a period of seven years from 1994 to 2000.

Percentage of Candidates who Qualified to Appeared in an Examination Over the Years

If the number of candidates who qualified in 1998 was 21200, what was the number of candidates who appeared in 1998?

A.

32000

B.

28500

C.

26500

D.

25000

Correct answer is C

The number of candidates appeared in 1998 be x.

Then, 80% of x = 21200   =>   x = (21200 x 100)/80 = 26500 (required number)