How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
profit of 13%
loss of 12%
loss of 10%
loss of 5%
Correct answer is C
s.p = N6900
%profit = 15%
%profit = \(\frac{s.p - c.p}{c.p}\) x 100%
15% = \(\frac{6900 - c.p}{c.p}\) x 100%
\(\frac{15}{100}\)c.p = N6900 - c.p
0.15 c.p = N6900 - c.p
1.15c.p + c.p = N6900
c.p = \(\frac{6900}{1.15}\)
= 6000.00
Now new S.P = N6600
profit = s.p - c.p = 6000 - 6600
= 600
%profit = \(\frac{600}{6600}\) x 100%
= 10%
3
4
5
6
Correct answer is A
No. of times = \(\frac{\text{Total distance}}{\text{Circumference of circle}}\)
= \(\frac{\text{Total distance}}{\pi d}\)
= \(\frac{1000m}{\frac{22}{7} \times 100m}\)
= \(\frac{1000 \times 7}{2200} = 3.187\)
= 3(approx.) nearest whole no.
The nth term of the sequence -2, 4, -8, 16.... is given by
Tn = 2n
Tn = (-2)n
Tn = (-2n)
Tn = n
Correct answer is B
sequence: -2, 4, -8, 16........{GP}
a = -2; r = \(\frac{4}{-2}\) = -2
nth term Tn = arn-1
Tn = (-2)(-2)^n-1
Tn = (-2)1 + n - 1
Tn = (-2)n
If y = \(\frac{(2\sqrt{x^2 + m})}{3N}\), make x the subject of the formular
\(\frac{\sqrt{9y^2 N^2 - 2m}}{3}\)
\(\frac{\sqrt{9y^2 N^2 - 4m}}{2}\)
\(\frac{\sqrt{9y^2 N^2 - 3m}}{2}\)
\(\frac{\sqrt{9y^2 N - 3m}}{2}\)
Correct answer is B
y = \(\frac{(2\sqrt{x^2 + m})}{3N}\)
3yN = 2(\(\sqrt{x^2 + m})\)
\(\frac{3yN}{2} = \sqrt{x^2 + m}\)
(\(\frac{3yN}{2})^2 = ( \sqrt{x^2 + m})\)
\(\sqrt{\frac{9y^2N^2}{4} - \frac{m}{1}}\)
x = \(\frac{\sqrt{9Y^2N^2 - 4m}}{4}\)
x = \(\frac{\sqrt{9y^2N^2 - 4m}}{2}\)
The sum of the exterior of an n-sided convex polygon is half the sum of its interior angle. find n
6
8
9
12
Correct answer is A
sum of exterior angles = 360o
Sum of interior angle = (n - 2) x 180
360 = \(\frac{1}{2}\) x(n - 2) x 180(90o)
360 = \(\frac{1}{2}\) x(n - 2) x 90o
\(\frac{360}{90}\) = a - 2
4 = n - 2
n = 4 + 2 = 6