How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
In the diagram, find the size of the angle marked a°
60o
80o
120o
160o
Correct answer is B
2 x s = 280°(Angle at centre = 2 x < at circum)
S = \(\frac{280^o}{2}\)
= 140°
< O = 360 - 280 = 80°
60 + 80 + 140 + a = 360°
(< in a quad); 280 + a = 360
a = 360 - 280
a = 80°
In the diagram, < QPR = 60o
< PQR = 50o
< QRS = 2xo
< SRP = 3xo
< UQP = yo and RS//TU
calculate y
102o
78o
70o
60o
Correct answer is A
< RQT = < QRS = 2x (Alternate angles). But in \(\bigtriangleup\) PRQ
50 + 60 + (2x + 3x) = 180o(Angles in a triangle)
110 + 5x = 180o
5x = 180o - 110 = 70o
x = \(\frac{70}{5}\) = 14o
Also y + 50 + 2(14) = 180o
y + 50 + 28 = 180o
y = 180 - 78
y = 102o
In the diagram, PX is a tangent to the circle and RST is an equilateral triangle. Calculate < PTS
60o
90o
120o
150o
Correct answer is C
\(\bigtriangleup\) RST is equilateral triangle, hence
< TRS = < RTS = < RSt = 60o
But < PTR = 60o(Angle between a chord and a tangent at the point of contact = Angle in the alt. segment). From the diagram < PTS = < PTR + < RTS
= 60o + 60o = 120o
19.5cm2
15.0cm2
13.0cm2
9.3cm2
Correct answer is B
Perimeter of \(\bigtriangleup\) PQR = PQ + QR + PR
24cm = 6cm + 8cm = PR
24 = 14 + PR
PR = 24 - 14 = 10cm
Area of \(\bigtriangleup\) PRS = \(\frac{1}{2} \times 10 \times 3cm^3\)
= 15cm3
25o
65o
115o
130o
Correct answer is B
x = 65o (An interior angle of a cyclic quadrilateral = opposite exterior angle).