How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Simplify \(\frac{\log \sqrt{8}}{\log 4 - \log 2}\)
\(\frac{2}{3}\)
\(\frac{1}{2} \log 2\)
\(\frac{3}{2}\)
\(\log 2\)
Correct answer is C
\(\frac{\log\sqrt{8}}{\log 4 - \log 2} = \frac{\log 8\frac{1}{2}}{\log (\frac{4}{2})}\)
= \(\frac{8 \frac{1}{2}}{\log (\frac{4}{2})}\)
= \(\frac{\frac{1}{2} \log 2^3}{\log 2}\)
= \(\frac{3}{2} \frac{\log 2}{\log 2}\)
= \(\frac{3}{2}\)
If x \(\alpha\) (45 + \(\frac{1}{2}y\)), which of the following is true>?
x varies directly as y
x varies inversely as y
x is partly constant and partly varies as y
x vries jointly as 45 and directly as y
Correct answer is C
No explanation has been provided for this answer.
If \(2^n = 128\), find the value of \(2^{n - 1})(5^{n - 2})\)
5(106)
2(106)
5(105)
2(105)
Correct answer is D
2n = 128
2n = 27
n = 7
(2n - 1)(5n - 2) = (2n - 2.2)(5n - 2) put n = 7
(2n - 1)(5n - 2) = 2(2n - 2 x 5n - 2)
= 2(2 x 5)n - 2
= 2(10n - 2) put n = 7
(2n-1)(5n-2) = 2(105)
If cos (x + 25)o = sin 45o, find the value of x
20
30
45
60
Correct answer is A
cos(x + 25o) = sin 45o
using cos \(\theta\) = sin(90 - \(\theta\))
cos(x + 25o) = cos(90 - 45)
cos(x + 25o) = cos 45
x + 25 = 45
x = 45 - 25
x = 20o
If tan x = 1, evaluate sin x + cos x, leaving your answer in the surd form
2\(\sqrt{2}\)
\(\frac{1}{2} \sqrt{2}\)
\(\sqrt{2}\)
2
Correct answer is C
tan x = 1; x = tan-1(10 = 45o
sin x + cos x
= sin 45o + cos 45o
= \(\frac{\sqrt{2}}{2} + \frac{\sqrt{2}}{2}\)
= \(\frac{\sqrt{2} + \sqrt{2}}{2}\)
= \(\frac{2\sqrt{2}}{2}\)
= \(\sqrt{2}\)